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高職數學 求救~~

(1) (y-k)^2 = 4p*(x-h)

L: x = -1 => p = 1

V = (1,2) => (y-2)^2 = 4*(x-1)

4x = y^2 – 4y + 8


(2-1) (y-k)^2 = 4p(x-h)

L: x = -1
 
V = (1,3) => p = 1 + 1 = 2

8(x – 1) = (y – 3)^2

8x = y^2 – 6y + 17

(2-2)


 
V = (3,2), F = (1,2)

=> p = 3-1 = 2

=> L: x = 3 + p = 5

=> -8(x-3) = (y-2)^2


(2-3) A=(6,4)

(y-3)^2 = 4p*(x-2)

(4-3)^2 = 4p(6-2)

=> p=1/16

(y-3)^2 = (x-2)/4


(2-4) A=(2,3), B=(-1,6), L: x=1

=> (x-1)^2 = 4p(y-k)

=> 1=4p(3-k), 4=4p(6-k)

=> k=2, p=1/4

=> (x-1)^2 = y-2

1x1.trans 高職數學 求救~~
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